Logical operator || in javascript, 0 stands for Boolean false?

I happened to know the following code

Here is the code, and very simple:

var test = 0 || -1 ;
console.log(test);

then the output in the console is -1

and somehow i am really new into the javascript,

all i think of is that the 0 stands for Boolean False in JS ,and so || operator seems to ignore the 0 and assign the value -1 to the variable

so am i right ?
i just want a confirm

• || — expr1 || expr2 (Logical OR)

  Returns expr1 if it can be converted to true; otherwise, returns expr2. Thus, when used with Boolean values, || returns true if either operand is true; if both are false, returns false..

• && — expr1 && expr2 (Logical AND)

  Returns expr1 if it can be converted to false; otherwise, returns expr2. Thus, when used with Boolean values, && returns true if both operands are true; otherwise, returns false.

All values in Javascript are either “truthy” or “falsy”.
The following values are equivalent to false in conditional statements:

• false
• null
• undefined
• The empty string "" ( '')
• The number 0
• The number NaN

All other values are equivalent to true.

So… var test = 0 || -1 ; returns -1.

If it was var test = 0 || false || undefined || "" || 2 || -1 it would return 2

Logical operator on MDN

You can use Nullish coalescing operator (??)

The nullish coalescing operator (??) is a logical operator that
returns its right-hand side operand when its left-hand side operand is
null or undefined, and otherwise returns its left-hand side operand.

Only null and undefined will be falsey. 0 will be considered true. But take care: an empty string will be considered true too!

console.log('0 ?? 1  ->', 0 ?? 1) // expected output: 0
console.log('null ?? 1  -> ', null ?? 1) // expected output: 1
console.log('undefined ?? 1  ->', undefined ?? 1) // expected output: 1
console.log('"" ?? 1  ->', "" ?? 1) // expected output: ""